NERD alert:
Regarding the Wolverine using less air per shot because of it operating at a higher pressure level I did some math and came up with the following:
Wolverine: 500 cc bottle. 84 shots use 60 bar: 500cc x 60 = 30 Liters of air used. 30 / 84 = 0.357 Liters of air per shot.
S510: 287 cc cylinder, 29 shots use 40 bar: 287 x 40 = 11.48 Liters of air used. 11.48 / 29 = 0.395 Liters of air per shot.
Since the s510 is shooting a heavier pellet at roughly the same velocity as the wolverine the use of air is about the same for both rifles. (when looking at delivered energy per amount of air used)
18.1 / 15.9 = 1.138 x the weight. So if the wolverine shot the 18.1 grain pellet it would use approx: 1.138 x 357 cc = 407 cc
I know that the s510 has gotten a slightly longer (about 20" vs 17") barrel but the differences are minimal IMO
Regarding the Wolverine using less air per shot because of it operating at a higher pressure level I did some math and came up with the following:
Wolverine: 500 cc bottle. 84 shots use 60 bar: 500cc x 60 = 30 Liters of air used. 30 / 84 = 0.357 Liters of air per shot.
S510: 287 cc cylinder, 29 shots use 40 bar: 287 x 40 = 11.48 Liters of air used. 11.48 / 29 = 0.395 Liters of air per shot.
Since the s510 is shooting a heavier pellet at roughly the same velocity as the wolverine the use of air is about the same for both rifles. (when looking at delivered energy per amount of air used)
18.1 / 15.9 = 1.138 x the weight. So if the wolverine shot the 18.1 grain pellet it would use approx: 1.138 x 357 cc = 407 cc
I know that the s510 has gotten a slightly longer (about 20" vs 17") barrel but the differences are minimal IMO
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