Tuning FX Impact Mk2/M3 - reducing valve opening effort

I'm being too lazy to draw you a picture, but if you angle the surface at 45 degrees then the length of the surface will increase by the square root of 2 (approx 1.4) therefore the total force acting on that surface will be 1.4 times the original (say x). Hence the force acting parallel to the rod will be x * 1.4 / 1.4 which is back to the original value x. The correct math for a cone would be a bit different, but the principle still applies.
 
Last edited:
I don't think knocking the poppet off the seat is the problem, it's achieving the desired dwell once the poppet is in the air stream... so we're back to aerodynamic drag on the poppet. If we can't measure the real world drag we can't do the math. Manufacturers like to put the valve down a narrow well for convenience but this causes much more drag on the poppet.
 
Last edited:
  • Like
Reactions: qball
Sorry, my bad - 70% of the force will work along the rod axis.

Here you go:

In our case phi is 45* and cos45*=0.707

Assuming that original area was 1cm2 and pressure was 300 bar: F=3000N

Assuming that new area is 1.4cm2: F=4200N

Force working along the rod prior to the modification was 3000N - there was only one component Fx.

After the modification we can calculate Fx=F*cos45*=4200N*0.707=2969N which is lower than 3000N by a tiny margin. But it is lower.
 
Easy way to visualise this without doing maths is to imagine holding the cone between you finger & thumb & squeezing hard.
The cone will want to move / slide out of your grip.
Like if you squeeze an orange pip, it launches across the room.

If you want to reduce the force, make the step smaller by enlarging the diameter of the rod furthest from the poppet (& the hole that in runs in).