What determines the minum length of rifling needed to stabilize a 7.0 grain diabolo wad-cutter for precision & accuracy at 20 yards?
What determines the minum length of rifling needed to stabilize a 7.0 grain diabolo wad-cutter for precision & accuracy at 20 yards?
Yes!Taken literally, your question reads a little bit like "what determines the number 5?"
The minimum length is whatever it is. Are you asking about the physics it takes to estimate that length?
There's a tonne of variables that go into it, like how tight the barrel fits the pellet, the type of rifling, twist rate, when the rifling starts, etc etc.
A diabolo pellet does not need spin to stabilize it, it will aerodynamically stabilize Itself. It needs spin (gyroscopic force) to lower the dispersion and make it more accurate and precise at a given distance.You use twist rate to stabilize the projectile, not barrel length.
Not sure what your after,but there ,is no formula that gonna predict accuracy ,impact or if it’s in this zone of math ,it’s got to be right.. Especially with the mechanics of springers and the tuning. PCP might be more predictable.A di
A diabolo pellet does not need spin to stabilize it, it will aerodynamically stabilize Itself. It needs spin (gyroscopic force) to lower the dispersion and make it more accurate and precise at a given distance.
Refere to postings from @Ballisticboy.
I already have the twist rate required what I don't have is the optimal length of twist, is it 10 mm or 700 mm or something in between.
Stabilizing a diabolo has nothing to do with correcting its trajectory.Not sure what your after,but there ,is no formula that gonna predict accuracy ,impact or if it’s in this zone of math ,it’s got to be right.. Especially with the mechanics of springers and the tuning. PCP might be more predictable.
As for correcting it self. . Shoot on backwards. diablo Don’t mean they are cats. Smooth bore would be useless
A diabolo pellet does not need spin to stabilize it, it will aerodynamically stabilize Itself. It needs spin (gyroscopic force) to lower the dispersion and make it more accurate and precise at a given distance.
I’m not aware of such equation. Nor have I seen it discussed. As mentioned above, there have been barrels with minimal length of rifling at the end of the barrel and they did ok.Yes!
Exactly!
I have the equation that is actuality used to determine the required twist rate that includes all the variables for this pellet.
I have the internal ballistics curves to tune the rifle to efficiently launch this pellet.
What I don't have is an equation with all the variables that determine the minimum / optimal length of rifling required.
Do you know of such equation?
IZH used hammer forged Baikal barrels. The forging process for a barrel used in the Olympics and world competitions has 7 steps.Care to elaborate on your findings?
Dave
These single stroke pneumatics are less than 6 joules muzzle energy with velocities less than 600 ft/sec. 16 inches of rifling is just drag after the pellet reaches 450 ft/sec in ~ 4 inches.“The length of rifling was 2% longer than the total distance required for the pellet to reach the desired velocity.“
If I’m understanding correctly, if it takes 16.000” of barrel to achieve desired velocity, one would need to add 0.320” of barrel to have the proper length of rifling. ?
Dave
I saw 5 pellet group testing results for both the Walther top level 10 meter air rifle and top level 10 meter pistol. Both were shot from a vice and both had the exact same group size at 10 meters. This led me to ask the question.The 16” was only for an example to clarify if I understood correctly the rifling length relationship. Your response doesn’t clear that up any, only that we are only talking about Olympic guns apparently.
Dave